Official Quant thread for CAT 2013

Q: When one of the two circles having the ratio of their radii as x (not equal to 1) pass through the centre of other circle, the length of common chord for the two cases are found to be equal. Then x^2 + 1/x^2 =
(a) 3 (b) 4 (c) 6 (d) 8 (e) 9
plz post the approach..

@albiesriram said:
ratio of area of triangle FOE to area of triangle AOD??
really!! this is ur qs.??? :-o
@albiesriram is the answere 1:8
@sauravd2001 no..
@albiesriram its 1:16... P
@bullseyes no trolling sir
@albiesriram whats the answere sir?
@albiesriram 5:8
@albiesriram sorry sorry its 1:16

no 1:16 similar triangles will have square of the side ratio as the area ratio..

are i did it diferently

for aod we have base as 8 ....draw perpendicular bisector weh ave perpendicular as 3
for foe we have base as 2 and then drawing perpendicular bisector we have perpendicular as .75
then =(.5*.75*2)/.5*8*3=1:16
@Anivesh90 said:
Q: When one of the two circles having the ratio of their radii as x (not equal to 1) pass through the centre of other circle, the length of common chord for the two cases are found to be equal. Then x^2 + 1/x^2 =(a) 3 (b) 4 (c) 6 (d) 8 (e) 9plz post the approach..
Anyone??
@bullseyes said:
really!! this is ur qs.???
i have couple of more lining up. But those questions will spoil the quality of the thread . thats y posted this one ..
@Anivesh90 scratching my head. wait nearing the answer..

3??
@albiesriram said:
@Anivesh90 scratching my head. wait nearing the answer..3??
yes.. approach?

i screwed my exam like this only.................nt taking care of slly mistakes

@albiesriram post ur questions ??????????????????
@bullseyes said:
really!! this is ur qs.???
Of course not, it's CAT,04 Nov, Evening batch question...
@surajsrivastav said:
Of course not, it's CAT,04 Nov, Evening batch question...
and indeed answer is 1:16.. :-)
@Anivesh90 let any of the circle pass through the other center. now the distance between chord be say some k. kick the cicle to the other side to the center of the circle. now it will have the same chord length.. if we draw and visualize we will be kicking the circkle 2k times... use pythogorous then... u may end up in ratio of the radii of circles. and we can find that 1/x2+x2. correct me if i am wrong..