can u plz tell me how did u assume that angles as 120 deg(the circular part)and 90 degs(for the straight part):sad:
The st. parts are the rope around the boxes , so can be considered as tangents to circle .Hence the angle subtended from center will be 90 deg. if u check the dig. the circular part can b calc. as 360 - , here 60 is the angle of the vertex of the triangle formed by the radius of the circles with all sides being equal to 2r ,therefore equilateral triangle.
can u plz tell me how did u assume that angles as 120 deg(the circular part)and 90 degs(for the straight part):(
The st. parts are the rope around the boxes , so can be considered as tangents to circle .Hence the angle subtended from center will be 90 deg. if u check the dig. the circular part can b calc. as 360 - , here 60 is the angle of the vertex of the triangle formed by the radius of the circles with all sides being equal to 2r ,therefore equilateral triangle.
u r repeating 50 ^50 in both ..... in 5(....) and also in 25 .... similarily check for other terms.....
I am doing that becoz 50 can b written as 5*10=5*5*2 so in effective 50^50 is actually 5^50*5^50*2^50 since i counted 50 5's when i counted with 5 so i counted the other 50 5's with 25
I am doing that becoz 50 can b written as 5*10=5*5*2 so in effective 50^50 is actually 5^50*5^50*2^50 since i counted 50 5's when i counted with 5 so i counted the other 50 5's with 25
1> If f(x) is a function tat satisfies f(x).f(1/x) = f(x) + f(1/x) and f(4) = 65 .What will be the value of f(6).
a>37 b>217 c>64 d>non of these
2> The domain of defination of y=[ log {(5x - x^2)/4}] a> [0,4] b>[-4,-1] c>[0,5] d>[-1,5]
3>The domain of defination of y= 3/(4 - x^2) + log(x^3 - x) a> (-1,0) U (1,infinity) b> not 2 or -2 c> both a and b d>non of these
Happy solving ::satisfie:
-------------------------- Sometimes I think the surest sign that intelligent life exists elsewhere in the universe is that none of it has tried to contact us
for your first question, i dont really hav a clear cut methodology of solving, but one can do this question be observation:
put x=1, we get f(1).f(1)=2.f(1) from here we get f(1) to be 0 or 2
put x=4 and let f(1/4) be a 65a=65+a a=65/64 Now u can c a trend that f(4)=65= (4)^3+1 f(1)=2= 1^3+1 f(1/4)=65/64=(1/4)^3+1
So, then f(x)= x^3+1 therefore, f(6)=6^3+1=217 (Though this is just a jugaadoo solution and not a scientific method of approch)
Question2:
term inside log shudnt be equal to zero and should be >0
(5x-x^2)/4 is not equal to 0=> x is not equal to 0 or 5 (5x-x^2)/4>0 => x lies between 0 and 5
Therefore, x shud lie between 0 and 5, excluding 0 and 5, so i think the first choice shud be (0,4], otherwise nthin else fits
Question 3:
here too x^3-x is not equal to 0 and >0 => x is not equal to -1,1,0 nd lies between (-1,0)U(1, infinity)
4-x^2 is not equal to 0 => x is not equal to 2,-2. Therefore the answer shud be (c)
hi abhi , Thanx for the jugadoo sol. ,till the time v find any bettter sol. for it , i think this will b good enough. for the 2nd sol. even i tht it shud b (0,4] as 0 shud not show up in the sol. but the answer is ,looks like a wrong sol given in the book.
and in the 3rd sol. canu please explain hw u get tat x lies between (-1,0) as from the eq.-> x^3-x > 0 => x>0 or (x^2 - 1) >0 , in this quadratic eq. D>0 and a>0 .Therefore x is positive outside the interval , then hwcome the result satisfies (-1,0). ?????? 😞
and in the 3rd sol. canu please explain hw u get tat x lies between (-1,0) as from the eq.-> x^3-x > 0 => x>0 or (x^2 - 1) >0 , in this quadratic eq. D>0 and a>0 .Therefore x is positive outside the interval , then hwcome the result satisfies (-1,0). ?????? :(
qn: Vinay fires two bullets from the same place at an interval of 12 mins but shyam who is on a train approaching vinay hears the seacond after an interval of 11 min 30s. speed of sound =330m/s. Find the speed of train. ans:1. 660/23 2. 220/7 3. 330/23 4. 110/23.
qn: Vinay fires two bullets from the same place at an interval of 12 mins but shyam who is on a train approaching vinay hears the seacond after an interval of 11 min 30s. speed of sound =330m/s. Find the speed of train. ans:1. 660/23 2. 220/7 3. 330/23 4. 110/23.
I am having problems with the same question...anyone who has already solved this pls reply... Will post more ques tomoro
My train runs at the speed of 23*330 m/s ,ive invented a new super machine. Who wants the first ride.
------------------- Sometimes I think the surest sign that intelligent life exists elsewhere in the universe is that none of it has tried to contact us.
qn: Vinay fires two bullets from the same place at an interval of 12 mins but shyam who is on a train approaching vinay hears the seacond after an interval of 11 min 30s. speed of sound =330m/s. Find the speed of train. ans:1. 660/23 2. 220/7 3. 330/23 4. 110/23.
in 1 sec the bullet can travel 330 mtrs 1 sec=330 m 12 mins=330*12*60
and 30 secs =330*30
thus shyam approached vinay with a speed of 330*30(24-1)/30
,ive invented a new super machine
.