Quant Basics for Zeros in Quant - CAT 2012

MBA CAT 2024
610
@chandana.kushi said:
A circular wheel of circumference 600 cms completes 12 revolutions in 12 minutes. Find its speed in m/sec
In 12 minutes, the wheel travels 12 revolutions => Distance traveled = 600*12 cm = 72 m

Speed = Dist/Time = 72/(12*60) = 6/60 = 0.1 m/s ?
611
@felis.catus said:
1) length of sides of triangle are x+1,9-x,5x-3.the number of values of x for which the triangle is isoceles isD)3

3

612
@YouMadFellow thank you very much

i'm poor in aptitude

613
A circular wheel completes 12 revolutions in 12 minutes. Find the angular speed.

i need answer for this
614
A man takes 7.5 minutes to walk along the diagonal of a square field at the rate of 2kmph. The area of the square field is (in square metres):


answer please
615
@chandana.kushi said:
A man takes 7.5 minutes to walk along the diagonal of a square field at the rate of 2kmph. The area of the square field is (in square metres):answer please
0.3125
616
@chandana.kushi said:
A man takes 7.5 minutes to walk along the diagonal of a square field at the rate of 2kmph. The area of the square field is (in square metres):answer please
distance he walked.= 7.5/60 * 2= 1/4 km
=> 250 m
hence area= 250*250/2= 31250 ?
617
@maddy2807 thanks
618
@techsurge said:
0.3125
thanks
619
A circular wheel completes 12 revolutions in 12 minutes. Find the angular speed.


answer pls
620
@chandana.kushi said:
A circular wheel completes 12 revolutions in 12 minutes. Find the angular speed.answer pls
12*360/12*60=6 degree/sec
621
A man rides cycle for two third of the distance to be covered. Then his tire got punctured. He walks the rest of the distance and found that he took twice the time for walking compared to riding. What is the ratio of his cycling speed to that of his walking speed?

answer pls
622
@chandana.kushi said:
A man rides cycle for two third of the distance to be covered. Then his tire got punctured. He walks the rest of the distance and found that he took twice the time for walking compared to riding. What is the ratio of his cycling speed to that of his walking speed?answer pls
one very simple way is just assume distance be 3 km
so 2 km he cycled 1 km he walked .
assume he cycle for 1 hr so he walked for 2 hr .
so speed of cycle = 2/1
speed of walk = 1/2.
so speed of cycle/ speed of walk = 4:1
623
By increasing the speed of his car by 15 kmph, a motorist covers 300 km in an hour less than before. The original speed of the car was:
624
@chandana.kushi said:
By increasing the speed of his car by 15 kmph, a motorist covers 300 km in an hour less than before. The original speed of the car was:
60?
625
@maddy2807 how
626
@chandana.kushi said:
By increasing the speed of his car by 15 kmph, a motorist covers 300 km in an hour less than before. The original speed of the car was:
let x be original speed and so original time 300/x
new speed (15 + x) new time (300/x - 1)
so x * 300/x = (15 + x)*(300/x - 1)
300 = (15 + x)*(300/x - 1) now you can solve it or put options ... to see which value satisfy ... 60 satisfy ..

627
@hedonistajay k thanks
628

I hv a doubt in proft and loss ques.
D sprng blance of a tradr shws 1kg for an actual wt of 750gm. Find d proft or loss % if d tradr marks d price at 10% abv d cost price.
A. 46.67% proft
B. 46.67% loss
C. 43.33% proft
D. 43.33% loss

629
@gr8sab said:
I hv a doubt in proft and loss ques. D sprng blance of a tradr shws 1kg for an actual wt of 750gm. Find d proft or loss % if d tradr marks d price at 10% abv d cost price. A. 46.67% proft B. 46.67% loss C. 43.33% proft D. 43.33% loss
say 1 kg cp = 100
so sp of 1 kg = 110
now he is selling 750gms for 110
whose cp is actually 75
so 35/75*100 = 7/15*100 = 7/3*20 = 7*6.66 = 46.6 profit
Option A