Quant Basics for Zeros in Quant - CAT 2012

MBA CAT 2024
570
@viewpt but he has mentioned only 4 digits ..was wondering if it is divided by 16???
571
@anjali_sng it does not matter if the number is divisible by 4 and 8... example 24 and 48..
572
@RanveerS said:
@viewpt but he has mentioned only 4 digits ..was wondering if it is divided by 16???
if 4 digit mentiones then i think we can't tell..
573
@RanveerS said:
@anjali_sng it does not matter if the number is divisible by 4 and 8... example 24 and 48..
cant we chck that way??? n 24 and 48 ?????
574
@viewpt
@anjali_sng i think what we can do is check whether it is divisible by 16 and not by 24 ..what say??
575

pllzzz ans this thing

cant we check the divisibilty of factors of a number to find that numbers divisibility????
m confused...
576
@anjali_sng
@anjali_sng said: pllzzz ans this thing
cant we check the divisibilty of factors of a number to find that numbers divisibility????
m confused...
We can do so but only if the factors are co-prime (as in they have nothing in common between them) so for checking if a number is divisible by 24, we cannot check 6 and 4 or 12 and 2, we have to check 8 and 3. (For example, check if 36 is divisible by 24 - using 6 and 4 will give a "yes", which is wrong!) or to check if a number is divisible by 54 we can check 27 and 2 (but not 9 and 6, which have 3 as a common factor)

The simplest way to do this "co-prime factor" thing is to write the number in the form of product of its primes - for example 24 is 2^3 x 3^1 so we check 8 and 3. Similarly if we want to check if a number is divisible by 45 = 3^2 x 5^1 we can check for 9 and 5.

Now 32 is 2^5 and so we can not check with any smaller values. But see the divisibility test for powers of 2 - we use last digit for 2, last 2 digits for 4, last 3 for 8...so we should use last 5 for 32.

regards
scrabbler
577
A Russian luxury pen maker sells €˜x €™ pens to a supermarket called Large Bazaar at a total price of . If the Large Bazaar sells all the pens at a total price of , find the maximum loss that could have been incurred by the Large Bazaar.

700
1000
1225
1300
578
@scrabbler said:
@anjali_sng
We can do so but only if the factors are co-prime (as in they have nothing in common between them) so for checking if a number is divisible by 24, we cannot check 6 and 4 or 12 and 2, we have to check 8 and 3. (For example, check if 36 is divisible by 24 - using 6 and 4 will give a "yes", which is wrong!) or to check if a number is divisible by 54 we can check 27 and 2 (but not 9 and 6, which have 3 as a common factor)The simplest way to do this "co-prime factor" thing is to write the number in the form of product of its primes - for example 24 is 2^3 x 3^1 so we check 8 and 3. Similarly if we want to check if a number is divisible by 45 = 3^2 x 5^1 we can check for 9 and 5.Now 32 is 2^5 and so we can not check with any smaller values. But see the divisibility test for powers of 2 - we use last digit for 2, last 2 digits for 4, last 3 for 8...so we should use last 5 for 32.regardsscrabbler
ty for such an explanation...
579
@Akashmad said: A Russian luxury pen maker sells €˜x €™ pens to a supermarket called Large Bazaar at a total price of . If the Large Bazaar sells all the pens at a total price of , find the maximum loss that could have been incurred by the Large Bazaar.
700
1000
1225
1300
1300. Minimum of quadratic 3x^2 - 120x - 100

regards
scrabbler
1 Like
580

if n= 2^4*3^2*7^3*k is a perfect square as well as a perfect cube, find the total no of factors of the least value of k given k is natural no????

581
@anjali_sng said: if n= 2^4*3^2*7^3*k is a perfect square as well as a perfect cube, find the total no of factors of the least value of k given k is natural no????
60...

regards
scrabbler
582
@scrabbler said:
60...regardsscrabbler
ya how???????
583
@anjali_sng said: if n= 2^4*3^2*7^3*k is a perfect square as well as a perfect cube, find the total no of factors of the least value of k given k is natural no????

Perfect square and perfect cube means perfect 6th power. Smallest case n = 2^6*3^6*7^6 which means smallest k is 2^2*3^4*7^3 and hence number of factors is (2+1)(4+1)(3+1) = 60

regards
scrabbler
584

hi puys!! I have a problem with hoe to approach the below question, pls help me (i know its a silly question, pls bare it
1)ratio of the number of students in three classes a,b and c is 3:7:8 if ten students leave c and join b, the ratio of the number of students in b and c would reverse. find the total number of students in three classes.
a)150

b)160

c)180

d)210

585
@saravankumar said:

hi puys!! I have a problem with hoe to approach the below question, pls help me (i know its a silly question, pls bare it 1)ratio of the number of students in three classes a,b and c is 3:7:8 if ten students leave c and join b, the ratio of the number of students in b and c would reverse. find the total number of students in three classes. a)150

b)160

c)180

d)210

let no of students in class a,b, c are 3x,7x and 8 x respectively.
According togiven condition
(7x+10/8x-10 )=8/7
49x+70=64x-80
15x=150
x=10
So total student 3x+7x+8x=18x=18*10=180
586
@saravankumar said:

hi puys!! I have a problem with hoe to approach the below question, pls help me (i know its a silly question, pls bare it 1)ratio of the number of students in three classes a,b and c is 3:7:8 if ten students leave c and join b, the ratio of the number of students in b and c would reverse. find the total number of students in three classes. a)150

b)160

c)180

d)210

180
587
@gaurav23march Thanks Buddy 😃
588
@challenger90 thanks buddy 😃
589

here i come again with a Dumb question ,Pls Help


X, Y and Z are three quantities. X varies inversely with Y when Z is constant, and Y varies inversely with Z when X is constant. When Y = 8, and Z = 7, X = 30. Find X if Y = 16 and Z = 21.

a) 5 b) 8 c) 10 d) 15

1 Like