Quant Basics for Zeros in Quant - CAT 2012

if length of a rectangle is increased of 40% and breadth is
decreased by 40%.wht is the net effect on the area?
pliz tell me the trick??also



area decreased by 16%...

thankssss again.......

After the division of a number successively by 3, 4 and 7, the remainders obtained are 2, 1 and 4respectively.
What will be the remainder if 84 divides the same number?

a. 80
b. 75
c. 41
d. 5


number = 3k + 2
k = 4n + 1
n = 7m + 4

take m = 0 , n = 4 , k = 17

and smallest such number = 53

so , 53 mod 80 = 53
Progression

1-Find the common ration of the GP whose 1st and last term are 25 and 1/625 and the sum of the GP is 19531/625.

2-Find the no. of terms in GP whose 1st term is 16 , sum is 1365/64 and common ratio is 1/4.

3-If x
4-If (1^3-t1)+ (2^3-t2)+(3^3-t3)+(4^3-t4)+............(n^3-tn)=n^2(n-3)/4, find tn where t1,t2,t3.....tn are the term of series
sanu8080 Says
Find the soln in the attached file plzz



thank you for the help but they are not correct moreover i need solution and procedure and not just answer keys....

BDW for prob 1 even i am getting 1/5 but its incorrect!

Ya, this will be useful.

Iam collecting quant tips and tricks in this site..
Home - Quant Fundas for MBA GMAT CAT XAT MAT
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3x-4y+2z=0 & 4x-2y-z=0
find x:z:y.

from 2nd eqn, we get z = 4x-2y. put this value in eqn 1st. u will get
11x= 8y , i.e. x:y = 8:10, now put this value in the 1st or 2nd eqn, u will get x:y:z

hi this is priti srivastava........ here is ur solution :

let the nos. be 4x and 7x. and the no. to be added be y.
so, (4x+y) + (7x+y) = 75 => 11x + 2y = 75 --------------- eqn(i)
and, (4x + y) / (7x +y ) = 8/17 => 12x + 9y = 0 -----------eqn(ii)
solve these two eqns. u will get y = -12.

Hi Puys,

Can anybody post the approach used in allegation type questions??

Thanks

hi this is priti srivastava........ here is ur solution :

let the nos. be 4x and 7x. and the no. to be added be y.
so, (4x+y) + (7x+y) = 75 => 11x + 2y = 75 --------------- eqn(i)
and, (4x + y) / (7x +y ) = 8/17 => 12x + 9y = 0 -----------eqn(ii)
solve these two eqns. u will get y = -12.



yeah -12 indeed
Inequalities :-

The expressions like 3x + 1 = x 3 and x2 3x = 0 are equations. But which type of expressions is called "inequations". When a statement written is neither true nor false until and unless it is replaced by some numeral value, is called an open sentence. E.g. 7x + 5 > 19 is such that no conclusion can be made from this unless x is replaced by some numeral values.
Now we can define inequalities as a sentence which says that one thing is not equal to another. The two sides are joined together by one of the following:
> (greater than);
(greater than or equal to)
(less than or equal to)

Example: 3x + 1 > x 3 or x^2 3x 0
As is the case with equations, they are ordered by degree and by the number of unknowns.
In the above two examples, the first will be a linear inequality with one unknown and the second will be
quadratic inequality with one unknown.

Solving Inequations On the basis of the laws of inequality, we have the following working rules.
1. Rule of Addition and Subtraction: Adding or subtracting a fixed number to each side of an inequality produces an equivalent inequality.
Example: Adding 2 to each side of the inequality x 2 1 is equivalent to x 3.
2. Rule of multiplication/division by a positive number: All terms on both sides of an inequality can be multiplied or divided by a positive number.
3. Rule of multiplication/division by a negative number: If all terms on both sides of an inequality are multiplied or divided by a negative number, the sign of the inequality will be reversed.
Some important properties to remember in Inequalities...
1) a^2 + b^2 + c^2 > = ab + bc + ca
2) (n!)^2 > n^n , for n > 2
3) For integers , 24) a^2*b + b^2*c + c^2*a > = 3abc
5) a/b + b/c + c/d + d/a > = 4
6) a^4 + b^4 + c^4 + d^4 >= 4abcd
Some important properties to remember in Inequalities...
1) a^2 + b^2 + c^2 > = ab + bc + ca
2) (n!)^2 > n^n , for n > 2
3) For integers , 24) a^2*b + b^2*c + c^2*a > = 3abc
5) a/b + b/c + c/d + d/a > = 4
6) a^4 + b^4 + c^4 + d^4 >= 4abcd


thanx buddy

I think solution for this ques is not correct
10. Some articles were bought at 6 articles for Rs. 5 and sold at 5 articles for Rs. 6. Gain percent is:

Hi, myself ananth and new to PG,

I started my preparation by last month with numbers, So plz help.

Can anyone give the explanation for the following Question, from AP,


*All terms of the AP are natural numbers. The sum of its nine consecutive terms, beginning with the first, is larger than 200 and smaller than 220. Find the progression if its second term is equal to 12?

I think solution for this ques is not correct
10. Some articles were bought at 6 articles for Rs. 5 and sold at 5 articles for Rs. 6. Gain percent is:



is it 44%???
I think solution for this ques is not correct
10. Some articles were bought at 6 articles for Rs. 5 and sold at 5 articles for Rs. 6. Gain percent is:

Hey,
Ans is 42.84%
Articles were bought at 6 for 5 rs.
So calculate the articles sold on same price ,i.e., 4.16.
Now put the values in the formula:
goods left/goods sold*100
1.84/4.16*100= 42.84%

*All terms of the AP are natural numbers. The sum of its nine consecutive terms, beginning with the first, is larger than 200 and smaller than 220. Find the progression if its second term is equal to 12?


the answer is 8,12,16,22.......

Hi, myself ananth and new to PG,

I started my preparation by last month with numbers, So plz help.

Can anyone give the explanation for the following Question, from AP,


*All terms of the AP are natural numbers. The sum of its nine consecutive terms, beginning with the first, is larger than 200 and smaller than 220. Find the progression if its second term is equal to 12?

Hey,
U can find out the solution by using the formula of n terms of an A.P.
i.e. S=n/2(2a+(n-1)d)
first put S=201, as given in the question,
and, put a =12-d, where d= common difference
Now, when u solve this u'll get d=3._ which is fraction,
thus after a slight look u'll find that if u put S=216 then d will come up 4.
So the progression is: 8, 12, 16, 20, 24.....