If f(x) = |x + 1| + 2|x + 2| + 3|x + 3|, then the least possible value of f(x).
is there any method to solve this?
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I am getting 45. If AE=EC then shouldn't EAC=ECA be 40?
In how many ways can three flags, of colors red, blue and green can be arranged at the vertices of an equilateral triangle of side 5 m?
ans is 2
but why It can't be 1 (Do we have to consider anti clockwise and clockwise direction as well)
The solution is getting lengthy, need an approach which may save time in such questions.
Why is the -2 value does not satisfy the given equation?
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A contractor takes up a project and employs 100 equally ecient workers (x1, x2,.....x100) with the aim of completing the work in 51 days. They begin the work on schedule but because of a dengue outbreak in the area, the workers fall ill and on every second day, two workers leave the job site i.e., x1 and x2 leave after the 2nd day, x3 and x4 leave after the 4th day and so on. How many days does the contractor require to complete the work?
I tried this:
Let amount of work done by each is 1 unit so total work is 100x51= 5100
According to new condition, work on days are like: 100, 100, 98, 98, 96....
so, 5100= 2(n/2(200+(n-1)(-2))))
for this I am getting the answer as n=50 which obviously wrong. Answer should be 100. Can anybody point out where exactly I am going wrong?
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How to calculate time difference?
X started for A to B at exactly 12 noon. Y started from B to A at exactly 2:00pm. They met on the way at five past 4 and reached their destination at exactly same time. What time was it?
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let's consider a H.P to be 1/a , 1/b , 1/c where a,b,c are in AP
now if I take a = b = c that is AP with common difference of 0.
now 1/a , 1/b , 1/c will be an H.P , A.P or both?
I had this doubt because in question mentioned below I took a=b=c and marked as AP and GP @scrabbler @Shankarji
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