here pair of 3 are formed from backward. then cube of a no. ‘x'(here 2) less than or equal to is found for first pair like in square root method. the difference foloowed by next pair is written down .
Now a Multiplication factor is taken which is equal to the no. ‘x’ multiplied by 30(every time used when finding new multiplication factor).
x*30= M.F.
then we have to find a digit ‘m’ such that the (xm*(M.F.) + m^2)m should be less than the or equal to the remainder derived in fist step.
And the process goes on by taking new M.F as xm*30
xm*30=M.F’
then we find 3rd digit n such that
(xmn*M.F’ + n^2)n