@Faruq said:

A cyclist left point A for point B and travelled at the constant speed of 25km/h. when he covered the distance of 8.33 km, he was overtaken by a car that left point A twelve minutes after the cyclist and travelled at a constant speed too. When the cyclist travelled another 30km, he encountered the car returning from B. Assume that the car did nt stop at point B. Find the distance b/w A and B.

The cyclist covered 25/3 kms in 20 mins. The car started 12 minutes after the cyclist. Thus the car covers 25 kms in 24 minutes.

When the cyclist meets the car again, the car would have travelled 30 + 2x in 30/25 hours or 72 mins. Hence 30 + 2x/72 = 25/24, x = 22.5

Total distance = 8.33 + 30 + 22.5 = 60.83. (Weird number, am I wrong somewhere?)

@Faruq said: A cyclist left point A for point B and travelled at the constant speed of 25km/h. when he covered the distance of 8.33 km, he was overtaken by a car that left point A twelve minutes after the cyclist and travelled at a constant speed too. When the cyclist travelled another 30km, he encountered the car returning from B. Assume that the car did nt stop at point B. Find the distance b/w A and B.

@Aizen said:

Its 7.

7^776 mod 4 = (-1)^ 776 mod 4 =1

Multiply by 7.

I think it should be multiply by 49, first 7 from 7^777 and another from 7*4 = 28

so remainder will be 49 mod 28 = 21

@chillfactor said:

Basically we are looking for exponent of 6 in 100!

Exponent of 2 in 100! = 97

Exponent of 3 in 100! = 48

So, exponent of 6 will be 48

Hence 48 zeros, but answer should be in base 6

So, it will be 120

Since B has 20 in the end, means A and C together will have 60

It is mentioned that B triples their amount, so before that A and C must be having 20 and B must be having 60

But initially A tripled the amount that was with B

So, B must be having 20 in the starting

@Faruq said:

In a plane, there are ten points, exactly three of which are collinear. No other set of three points are collinear. Find the number of straight lines which can be formed by joining these ten points.

"

Post detailed Solution Also

Two points determine one line.

From 10 points, we have 10C2 lines.

However 3 of of them are collinear. They would form 1 line.

Thus 10C2 - 3C2 + 1

@Faruq said:

Solution B is prepared by evaporating some of the water contained in solution A, which contains water and sulphuric acid in the ratio 2 : 1. If solution B contains water and sulphuric acid in the ratio 1 : 2, what percent of the water in solution A has been evaporated to obtain solution B? >>

>>

(1) 50%

(2) 662/3%

(3) 75%

(4) 831/3%

@Faruq said: In a plane, there are ten points, exactly three of which are collinear. No other set of three points are collinear. Find the number of straight lines which can be formed by joining these ten points. "

Post detailed Solution Also

@Faruq said: In a plane, there are ten points, exactly three of which are collinear. No other set of three points are collinear. Find the number of straight lines which can be formed by joining these ten points. "

Post detailed Solution Also

@Faruq said:

Solution B is prepared by evaporating some of the water contained in solution A, which contains water and sulphuric acid in the ratio 2 : 1. If solution B contains water and sulphuric acid in the ratio 1 : 2, what percent of the water in solution A has been evaporated to obtain solution B?>>

>>

(1) 50%

(2) 662/3%

(3) 75%

(4) 831/3%

@Faruq said:

Solution B is prepared by evaporating some of the water contained in solution A, which contains water and sulphuric acid in the ratio 2 : 1. If solution B contains water and sulphuric acid in the ratio 1 : 2, what percent of the water in solution A has been evaporated to obtain solution B?>>

>>

(1) 50%

(2) 662/3%

(3) 75%

(4) 831/3%

@Faruq said:

Solution B is prepared by evaporating some of the water contained in solution A, which contains water and sulphuric acid in the ratio 2 : 1. If solution B contains water and sulphuric acid in the ratio 1 : 2, what percent of the water in solution A has been evaporated to obtain solution B?>>

>>

(1) 50%

(2) 662/3%

(3) 75%

(4) 831/3%

@Faruq said: The last digit of the LCM of (3^2003 - 1) and (3^2003 + 1) is (1) 8 (2) 9 (3) 4 (4) 6

@neerajagayatri said: There are 8 different books and 2 identical copies of each in a library. The number of ways in which one or more books can be selected is:a) 2^8 b)3^8-1 c)2^8-1 d)3^8We are given 3 different green dyes , 4 different red dyes and 2 different yellow dyes. The number of ways in which the dyes can be selected so that atleast one green dye and one yellow dye is selected is:a) 336 b) 335 c) 60 d) 59

@neerajagayatri said: There are 8 different books and 2 identical copies of each in a library. The number of ways in which one or more books can be selected is:a) 2^8 b)3^8-1 c)2^8-1 d)3^8We are given 3 different green dyes , 4 different red dyes and 2 different yellow dyes. The number of ways in which the dyes can be selected so that atleast one green dye and one yellow dye is selected is:a) 336 b) 335 c) 60 d) 59

@nitish_negi said: @gyrodceite How did you reduce 3^28 to 9^14? It don't get how it is done.

@Faruq said:

14. If x, y, z are positive irrational numbers and 9x2 + 29y2 + 9z2 = 30xy + 12yz, which of the following is true?>>

>>

(1) y = 1.5x>>

(2) x = 1.5y>>

(3) x = 0.6y>>

(4) y = 1.5z>>

@Faruq said:

30. What is the remainder when 7^777 is divided by 28?>>

>>

(1) 1>>

(2) 7>>

(3) 3>>

(4) 21>>

@Faruq said: The last digit of the LCM of (3^2003 - 1) and (3^2003 + 1) is (1) 8 (2) 9 (3) 4 (4) 6

@Faruq said:

30. What is the remainder when 7777 is divided by 28?>>

>>

(1) 1>>

(2) 7>>

(3) 3>>

(4) 21>>

@Faruq said:

30. What is the remainder when 7777 is divided by 28? >>

>>

(1) 1>>

(2) 7>>

(3) 3>>

(4) 21>>

4k + 3 = 7a. Thus 7.

Is the question not 7^7^7^7 mod 28?

@Faruq said:

30. What is the remainder when 7777 is divided by 28?>>

>>

(1) 1>>

(2) 7>>

(3) 3>>

(4) 21>>

@torqtech said:

I think it should be a multiple of 5!!

@Faruq said:

The last digit of the LCM of (3^2003 - 1) and (3^2003 + 1) is (1) 8 (2) 9 (3) 4 (4) 6

LCM x HCF = Product of two numbers

LCM = (3^2003 - 1)(3^2003 - 1)/2 = (3^4006 - 1)/2

3^2006 mod 100 is 29. (28 - 1)/2 = 14. Thus the last digit will be 4.

@shivs said: The weight of an iron bucket increases by 33.33% . . . when filled with water to 50 % of its capacity .... Which of these may be 50 % of weight of bucket when it is filled with water (Weights in integers only )Options :: a. 7 Kgs b. 6 Kgs c. 5 Kgs d. 8 Kgs ..

earlier i thought we just have to find wt of bucket

@shivs said: The weight of an iron bucket increases by 33.33% . . . when filled with water to 50 % of its capacity .... Which of these may be 50 % of weight of bucket when it is filled with water (Weights in integers only )Options :: a. 7 Kgs b. 6 Kgs c. 5 Kgs d. 8 Kgs ..

@chevy said:

hw many no of 1st 100 natural no's are relatively prime to 100 but not to 99?

P.S.-no OA

It will be 16.

Numbers relatively prime to 100 should will be non-multiples of 2 and 5. Numbers not co-prime to 99 will be multiples of 3 and 11.

Number of Mutiples of 3 but not of 2 or 5 and less than 100 = 13

Number of Multiples of 11 but not of 2 or 5 and less than 100 = 4

But 33 is common between the two. Thus 13 + 4 -1 = 16

Numbers n

@nitish_negi said: What will be the unit's digit of (1273) ^ 122! ? (please explain it in detail)

@tiwarishiva said:

yess bro. share ur approach plz

@invincible2910 said: There is a pond and in this pond there is a lotus flower, everday the number of lotus flowers doubles.On the Fortieth day the pond is filled to capacity.On what day is the pond half filled?

@shivs said: The weight of an iron bucket increases by 33.33% . . . when filled with water to 50 % of its capacity .... Which of these may be 50 % of weight of bucket when it is filled with water (Weights in integers only )Options :: a. 7 Kgs b. 6 Kgs c. 5 Kgs d. 8 Kgs ..

@nitish_negi said: What will be the unit's digit of (1273) ^ 122! ? (please explain it in detail)

@kungfu-panda said: @piyushrohella12 you are right .. but let me know the procedure ..

@Rage126 said: @tiwarishiva AB/6?

@tiwarishiva said: Ab is a hypotenuse in right angle triangle ABC. N is a point inside the triangle which divides the triangle in three equal parts.(ABN, CAN, BCN) . What is the distance between circumcentre of this triangle from N. 1. AB/4 2. AB/6 3. AB/3 4.2/(1+root3)

@shashikhawani said:

Namaskar Bhailog

_________________//|\\____________________

Chill Sir \\_______o//

I didnt get this one :

Divya works for Google that claims only 4 working days. In the 1st week of joining, she went for movies after 4 working days. On Friday, she noticed that the fraction p of the line is in front of her, while 1/q of the line was behind her. On Saturday, the same fraction p of the line was in front of her, while 1/(q+1) of the line was behind her. On Sunday, the same fraction p of the line was in front of her, while 1/(q+2) of the line was behind her. For how many values of p is this possible? (a) 3 (b) 1 (c) 2 (d) no such value (e) infinitely many

and

If n is any 3-digit prime number then which of the following statement(s) is(are) definitely true?

1. n divides 2^n – 2.

2. a^n + b^n is always divisible by (a + b) for a + b ≠ 0.

3. There always exist n consecutive composites numbers.

options re

1) Only 1

2) Only 2

3) Only 1 and 2

4) All statements are correct

How can we say that 1 and 3 are correct. Need explainations.

so they will always have even number of nos between them... so we cant have odd nos of consecutive composite nos..

@kungfu-panda said: Can anyone explain be the procedure for solving the below question The solution set for the inequation |x-1| + |x+2| < 2 .

@deedeedudu said:

I'm getting 16

@aragorn7 said:

i guess if we assume the quad to be a square. the angle will form a kite with the diagonals of the square, at the center of the circle. the angle will be 135. hence sum of all will be 540. if the answer is general then it should be 540 for any case including this one.

@chevy said:

hw many no of 1st 100 natural no's are relatively prime to 100 but not to 99?

@sowmyanarayanan said:

if that is the angle you mean

@chevy said:

hw many no of 1st 100 natural no's are relatively prime to 100 but not to 99?

@tiwarishiva said: A quadrilateral is inscribed in a circle.If an angle is inscribe in each of the segments outside the quadrilateral, then what is the sum of four angles? 1.270 2.360 3.540 4.720(with approach plz)