All the best. :)
[OFFICIAL] AIMCAT 1310 Discussion Thread (Please DON'T OPEN if you have not taken the test)
CAT & Related BSchools
Add more users
Invigilated.7th to 13th August.
All the best. :)
All the best. :)
@[559818:life99]...lol s please gimme 4 more marks.....currently oa 99%ile 98.61
@[525438:taurean11]haw how did you get the last two values?:(
Maine bhi yahi logic lagaya:P...hey bhagwan, 4 marks badaado please:P
solution galat hai..par key ke hisaab se shayad theek hai..mere 5 cases aaye the:4743420,4723422,4703424,4793426,4773428
2
its option 1 right?.....4+a+4+b=7+3+28+a+b=12a+b=4 ....also b can only be even....so (a,b)= (0,4) (2,2) and (4,0)
am i right ?
am i right ?
@[411127:sid2222000]arey bapre:P..mera toh (1) tha...3 in total..coz a+b=4 is one condition and a can take values as 0,2,4. apka 4th number kaha se aya?
@[559818:life99]Tera kya aaya tha....??Mera option (2)4
Posting my score for the 1st time..
QA- 30 (83.33) missed the cut off
VA- 59 (99.12)
Overall- 89(96.95)
PLz give suggestions for quant. Desperately need advice in it.
QA- 30 (83.33) missed the cut off
VA- 59 (99.12)
Overall- 89(96.95)
PLz give suggestions for quant. Desperately need advice in it.
i swear!! couldnt believe i got that wrong but solution dekhkhe santushti milgayi:P...waise what is the correct answer to Q. 4 of Section I??
Ahaa.....TIME strikes agn wid erratas....:PQ4 of 1st section.....Sum kuch aur hai aur solution kuch aur hi......:PGolmaal hai bhai sab golmaal hai.....:P
3
Section I - 42 - 95.15
Section II - 46 - 93.28
Overall - 88 - 96.67
*moaning like always*
nahin badh raha score :banghead:
Section II - 46 - 93.28
Overall - 88 - 96.67
*moaning like always*
nahin badh raha score :banghead:
oo sry... it's thr now..browser issues
31 for QA
38 for VA
31 for QA
38 for VA
results out.... but finding it bit wierd ... no sectional cut offs mentioned :S
when will we get results
got only 57
@[542948:MI8888] case 1 and 2 : when we subtract 2 in case 1, it means two cases where only single student gets all 5 fruits lets say stud A
in case 2 : subtracting 3 automatically have 2 scenario covered into case 1 for ex stud A getting all 5 fruits...
I suppose I am making sense to you.....
in case 2 : subtracting 3 automatically have 2 scenario covered into case 1 for ex stud A getting all 5 fruits...
I suppose I am making sense to you.....
@[115576:pratee] : we have to subtract 2 cases from total 3^5 cases:
Case - 1 : when from the 3 chosen guys only 2 get the fruits - 2^5 but it will also include the case when out of 2 only 1 get the fruit so we have to subtract that - (2^5 - 2) ...
Case - 1 : when from the 3 chosen guys only 2 get the fruits - 2^5 but it will also include the case when out of 2 only 1 get the fruit so we have to subtract that - (2^5 - 2) ...
(2^5-2) this -2 has already been taken into account in -3...when only one student gets all five fruits..isn't it??
@[588946:VINAY5890]
was there an option 5/36 ??
was there an option 5/36 ??
@[494200:professamit]: BAROBAR...
@[222373:Love_CAT] : since a+b should be positive so the soln a=-1 and b=1 wont work. Hence the answer would be 6.
@[115576:pratee] : I was getting 125/324
6C3*[3^5 - 3C2*(2^5 - 2) - 3]/6^5
6C3*[3^5 - 3C2*(2^5 - 2) - 3]/6^5
did u get the same thing
@[588946:VINAY5890] yeah if we go by this soln there was no such option
Thts the reason i wasted 10 mins n didn't mark anything
Thts the reason i wasted 10 mins n didn't mark anything
select 3 frm 6 in 6c3 , then x1+X2+x3=5(no of solutions)4c2 nd x1+x2+ x3+x4+ x5+x6=5(number of non negative solutions=10c5) so 6c3*4c2/10c5=10/21 , but no option in the qustion is 10/21
can u tell me wht were the options
ya i am wrong
in the question it ws mentioned that fruits should be distributed among exactly 3 students..
So from 3^5 don't we need to subtract 6ways in which 5fruits will be given to only one and two students....??
So from 3^5 don't we need to subtract 6ways in which 5fruits will be given to only one and two students....??
result kab hai?
6c3(select 3 out of 6 students)*3^5(each fruit can be given in 3 ways of the 3 students selected)/6^5 =5/8
"How does one reduce less mistakes in VA?" Less mistakes is a good thing! Anyway, you have answered your own question "always end up attempting a lot in II section". Attempt lesser questions, only the ones you are very sure of. I started with 10 mistakes in VALR in my earlier mocks, but analysi...
1
Less mistakes is a good thing! Anyway, you have answered your own question 
). If you are somehow sure of everything and still getting most questions wrong, then you need to get back to basics. Read regularly, and maybe get some material on grammar rules and stuff.
Off topic: Guys, slot booking for 1308 proctored is open..
1
@sanjeev.kataria(a+8)(b+7)=56 Now factorise 56.
Like 1*56 for it a=-7 b=49 or it can be a=48 b=-6 Do it for 2*28, 4*14 So a total of 2*3 waysNow for 7*8 a=-1 b=1 or a=0,b=1 but the latter is not possible.
Hence 7 values
Like 1*56 for it a=-7 b=49 or it can be a=48 b=-6 Do it for 2*28, 4*14 So a total of 2*3 waysNow for 7*8 a=-1 b=1 or a=0,b=1 but the latter is not possible.
Hence 7 values
anyone knows hw to reduce less mistakes in VA???
with QA nd LR u always know, if u r doing it rite or not. but no such thing with VA, so i always end up attempting a lot in II section and a lot of times a lot of dem go wrong too.
In 1310, attempted all in sec. II got 19 correct bt 11 wrong.
with QA nd LR u always know, if u r doing it rite or not. but no such thing with VA, so i always end up attempting a lot in II section and a lot of times a lot of dem go wrong too.
In 1310, attempted all in sec. II got 19 correct bt 11 wrong.
@[222373:Love_CAT] hw did u solve it??
i didnt even get hw d 3 values came of a came out??
i didnt even get hw d 3 values came of a came out??
@[564457:singhanand98] i did d same thing bt as far as i remember 81 wasnt even as an option.
the options were 80, 160, 161 and 169. ( not sure abt d last option).
i jst marked d answer as 80, it being d closest one.
the options were 80, 160, 161 and 169. ( not sure abt d last option).
i jst marked d answer as 80, it being d closest one.
not sure abt d last option).
Why a is always positive :mg:(a,b) (-7,49) is a valid soln. afa i can remember 7 was my answer
1
ans is 6?
@[605522:sanjeev.kataria] @[564457:singhanand98] The sum of the nth terms are given: 7+6(n-1) + 5+8(n-1) = 9000. n=643. The first series is 7,13,19,25,31,37,43,49,55,61.........the second one is 5,13,21,29,37,45,53,61,69,77,85.......the common terms are 13,37,61......which if observed are the 2nd...
2
anyone knows solution to probability problem (5fruits n 6students)...
OA : 45A/37C/8W - 103QA: 24A/21C/3W - 60VA: 21A/16C/5W - 43
Still not able to attempt more in VA I so scared with grammar that i have not touched the grammar ques in last 5 aimcats :((someone suggest something to improve upon it in short time
Still not able to attempt more in VA I so scared with grammar that i have not touched the grammar ques in last 5 aimcats :((someone suggest something to improve upon it in short time
1
Right you are sir, Itna careful tha, almost reluctant, ke sirf 19 kar paaya, fir bhi 3 errors is very unusual.
i expected a lot of 140s in this one as the exam felt on the easier side.Expecting an errata in quant if not then some very beautifully deceiving questions in quant..
3
In my opinion, they weren't tough, they were just quite lengthy.
1
hey guys,
i do believe RC's were on the tough side...
i do believe RC's were on the tough side...
jsut got 36 VA attempted 25 but unfortunately only 10 submittedis someone having same problem or it's with me only
@[564457:singhanand98] in d ap question i did d same, but 81 is not an option.
i think 3 options were 80, 160 and 161.
fourth i dont remember bt was greater dan all dese three.
so will d answer b 80??
i think 3 options were 80, 160 and 161.
fourth i dont remember bt was greater dan all dese three.
so will d answer b 80??
@[564457:singhanand98] i too did the same.
bt the problem is 81 isnt even an option.
d options were 80 160 161 169.
i marked 80 as it was d closest.
bt the problem is 81 isnt even an option.
d options were 80 160 161 169.
i marked 80 as it was d closest.
no problem
@[605522:sanjeev.kataria] For the second question...The equation can be written as (a+8)(b+7)=56Now here a is always positive and b can be positive or negative ... so a can take only 14 , 28, 56 ...3 values ...
1
@[588946:VINAY5890] dude i dont remember the answers or even the qstns!!wait a day or two and the results and solutions will be out!!sorry for disappointing u man!!
@[605522:sanjeev.kataria] For your first question ...The sum of first n terms of both the series is given ... n comes out as 642 ... now find the 642nd term of the series, which the smallest of the two ... now the nth common terms is 48n-35 ... now this should be less than the nth term of the ser...
1
when can the results be expected? shouldn't they be out by now?
where can I get pdf of this years CL mocks?
QADI - 19A 18C - 53VALR - 23A 19C - 53
total - 106
finally crossed the 50 barrier in sec. 2..really happy for that
total - 106
finally crossed the 50 barrier in sec. 2..really happy for that
4
And, was getting 2 answers for this one:
hw to solve this one:
7/b + 8/a = -1, where a and b are non-zero integers. For how many values of (a, b), is (a + b) positive?
hw to solve this one:
7/b + 8/a = -1, where a and b are non-zero integers. For how many values of (a, b), is (a + b) positive?
haan to %ile predict karne waale bhaiyo...kuch batao yaaron ki 75 pe kitne aa skte hn ??
pehli baar is season mein yaha tak pahucha hun..isliye utsukta ho rahi hai...( man i wish CAT could have hindi as well )
some people have a really good method here..
pehli baar is season mein yaha tak pahucha hun..isliye utsukta ho rahi hai...( man i wish CAT could have hindi as well )
some people have a really good method here..
There are two arithmetic progressions, A1 and A2, whose first terms are 7 and 5 respectively and whose common differences are 6 and 8 respectively. How many terms of the series are common in the first n terms of A1 and A2, if the sum of the nth terms of A1 and A2 is equal to 9000?
hw to solve ...
hw to solve ...
@[334799:swagat.sid] can you please mail me last year aimcats?? have pm'd you my id ..thanks in advance