May this be bigger and better than ever. :D :D
Results of MMDT '11. (To show you that this team follows a rich tradition)
Name/P...
11
11
Right now, we have started this thread to discuss possible members and related things so that we can post a legit nomination for the creation of this team.
May this be bigger and better than ever. :D :D
Results of MMDT '11. (To show you that this team follows a rich tradition)
Name/P...
May this be bigger and better than ever. :D :D
Results of MMDT '11. (To show you that this team follows a rich tradition)
Name/P...
:D
606
One number added, average increases by 1.
Og avg = 55
New avg = 56
New number brings in 13 more which can be distributed between the 13 new numbers to increase avg by 1.
Originally there were 12 no's. Let the first 11 numbers be the 11 smallest distinct natural no's. S11 = 66
12th...
Og avg = 55
New avg = 56
New number brings in 13 more which can be distributed between the 13 new numbers to increase avg by 1.
Originally there were 12 no's. Let the first 11 numbers be the 11 smallest distinct natural no's. S11 = 66
12th...
2
Q. M is a set of distinct positive integers whose average is 55. If a number 68 is added to this set, the average increases by 1. What is the largest number that can occur in this set?
Easy hai, concepts ke liye achcha hai.
Easy hai, concepts ke liye achcha hai.
I am preparing some concept topics for discussion here. We will go through them together. Ek concept booklet tayyar ho jaaye bas.
5
Filhaal main ek sectional analyze kar raha hu, jo sahi lagte hai daalunga.
I was going to go through the thread after I am done analyzing.
I was going to go through the thread after I am done analyzing.
1
Thode aur ques daal na...I had emptied my basket yesterday.Did you go through them?Some of them are nice,conceptual ques. Will have to research for more ques.
Ab hum jaise log mock ka load lene lag gaye hai na, toh dikhna band ho gaya hai saala.
1
Didn't strike that C has to be negative since (A>0) I.e product of roots <0 Nice work,man. :)
Thoda sochna pada...Novel question tha mere liye.Hadn't seen anything like this before. I was thinking f(0)<0 as imaginary roots. :P See, (x-alpha)(x-beta)<0 for f(0)<0 either x-alpha>0 and x-beta<0 alpha can be 1,2 and beta can be -1,-2,-3 =6 solutions. or x-alpha...
1
thanks mate! nice soln
@[282649:antorikroy],check out the solution given here
http://gmatclub.com/forum/a-fair-coin-is-tossed-10-times-what-is-the-probability-that-88393.html
apparently faad q hai yeh..
http://gmatclub.com/forum/a-fair-coin-is-tossed-10-times-what-is-the-probability-that-88393.html
apparently faad q hai yeh..
1
coins wala Q kisi ko aaya ?
..simple lag raha tha bt aaya nahi
..simple lag raha tha bt aaya nahi
Haan yaar, bahot easy tha. Har test ke first question ka usually main yehi karta hu. :P
too much of speed reading? I was also wondering ki easy to tha...
Arey yaar, tera solution padhne ke baad realize kiye ke condition f(0)<0 hai, main kabse f(alpha or beta) < 0 soch raha tha..
oye 18 ans hai kya?
basically C negative hona chahiye
product of roots =C/Aif a is +ve then c has to be -ve and that will happen if either alpha or Beta are -ve.
alpha has 4 -ve valuesbeta has 3 postive values12 iske bante hai
similarly alpha has 2 positive and beta has 3 negative v...
basically C negative hona chahiye
product of roots =C/Aif a is +ve then c has to be -ve and that will happen if either alpha or Beta are -ve.
alpha has 4 -ve valuesbeta has 3 postive values12 iske bante hai
similarly alpha has 2 positive and beta has 3 negative v...
1
Q. Given that f(x) = Ax2 + Bx + C (A > 0). If f(x) = 0 has integral roots α and β such that –4 ≤ α ≤ 2 and –3 ≤ β ≤ 3, then for how many distinct pairs (α, β), f(0)< 0 ?
abe gharelu warelu sab dikhawa hai..seaface pe daru peete hai sir
3
:)
Time ki baat hai....Gharelu se kaise daaru piyega :P
Time ki baat hai....Gharelu se kaise daaru piyega :P
1
I love old monk trance music and driving and of course counter strike...gt rusty now
1
MMDT confy has started.
Interested people may join in.
Interested people may join in.
hahaha...i hope nt d defaulters list .....so wer u wrking now?
ohh i think i remember reading ur name smwhere. face se to janta hi hoonga..yaar me bhi 2010 passout hi hoon btw!
@Zzeke said: Chalo,tab tak thoda time pass...Guys,let's know each other meanwhile.Kya kya shauk hai yahan loge ke apart from doing alpha,beta and what are you good at(No worthwhile activity should be mentioned!)Like I love clubbing,hip hop music,chicks,workout,eve teasing...Saare aayiisshoooooo waale shauk.
Chinta ta chita chita!
I'm a very gharelu type of insaan. But I <3 Food and travelling :)
I'm a very gharelu type of insaan. But I <3 Food and travelling :)
Ad Majora Natus Sum. | thepai.wordpress.com
arey manmeet i saw dat u frm TSEC....me too 2010 passout IT
1
Chalo,tab tak thoda time pass...
Guys,let's know each other meanwhile.
Kya kya shauk hai yahan loge ke apart from doing alpha,beta and what are you good at(No worthwhile activity should be mentioned!)
Like I love clubbing,hip hop music,chicks,workout,eve teasing...Saare aayiisshoooooo wa...
Guys,let's know each other meanwhile.
Kya kya shauk hai yahan loge ke apart from doing alpha,beta and what are you good at(No worthwhile activity should be mentioned!)
Like I love clubbing,hip hop music,chicks,workout,eve teasing...Saare aayiisshoooooo wa...
captain sahab weekend to nahi mana rahe hai?
4
Lol...I swear this is the first meeting where I am making it on time. :P
I am just a jerk. :D
I am just a jerk. :D
1
im online dint get any invite....captains sirs guide us
1
i and antorik are also onli9ne ...kaha aana hai..?
1
kahan aana hai?
1
If mean and mode of a distribution are 4 and 28 respectively, then find the median for the distribution. Add to my a12 b14 c16 d18 eNone of these
@[291744:ashishpai2001]
A-P-B,Nice method.
Point kaise nikale?Section formula?
A-P-B,Nice method.
Point kaise nikale?Section formula?
1
The point should always lie on the line dividing PA and PB in ratio 2:1
So,I guess it has to be the straight line passing through origin dividing the triangle in ratio 2:1
BCZ
height x base1=2(height x base2)
height is same.
So,ratio is ultimately-
Base1=2 times Base2
So,I guess it has to be the straight line passing through origin dividing the triangle in ratio 2:1
BCZ
height x base1=2(height x base2)
height is same.
So,ratio is ultimately-
Base1=2 times Base2
1
n.o.t taking x as 1....visually none of options givs triangle opa = 2pob
1
None????
If A-P-B, then P (4,1/3) which satisfies none of the options.
If A-P-B, then P (4,1/3) which satisfies none of the options.
1
Let O be the origin and A, B be two points having coordinates (0, 1) and (6, 0) respectively. If a point P moves in such a way that the area of ∆OPA is always twice the area of ∆POB, then P lies on Add to my ay2 = 9x2 bx2 = -9y2 cx2 - 9y2 = 0 dy2 = – 9x2 eNone of these
Didn't check the original eq.When you keep y=6 then log2 (5-y) will be invalid.
:( Nice ques.
:( Nice ques.
1
Saale, text chat. Ab tu paka raha hai. Chup chaap se aa ja. :P
Aur meri fatt chuki hai ab... Quant jald hi sambhle toh achcha hai. Sirf accuracy ka load, baaki attempts, concepts, etc. most bases are covered. :(
Haan, mocks main decent ban rahe hai na toh UDT khud hi ban gayi.. :)
Aur meri fatt chuki hai ab... Quant jald hi sambhle toh achcha hai. Sirf accuracy ka load, baaki attempts, concepts, etc. most bases are covered. :(
Haan, mocks main decent ban rahe hai na toh UDT khud hi ban gayi.. :)
1
Ghar se talk karne ki ichha nahi hoti yaar. Too many distractions on a Sunday Night :D
BTW 40 days to CAT!!!
And you're in UDT too?? Maan gaye ustad :D
BTW 40 days to CAT!!!
And you're in UDT too?? Maan gaye ustad :D
Abey gtalk confy.. 10:00 pm.
Online rakha hai. :D
Online rakha hai. :D
Arey sahi tha ye question.
Important cheez ye hai ke, log main variable daalo toh ek aur condition check karni bach jaati hai..
Second time ye hua hai mere saath. :splat:
Important cheez ye hai ke, log main variable daalo toh ek aur condition check karni bach jaati hai..
Second time ye hua hai mere saath. :splat:
1
acha we gt root(xy) as 6 so xy = 36 so 9&4 combination possible but dis does nt satisfy 1st eqn ,....but 8&4 does...so xy=32...
itna sochta bhi nahi mein :P
itna sochta bhi nahi mein :P
2
Hmm, quant main kaisa?
Aur accuracy?
Aur accuracy?
Mera ab ulta ho raha hai, Quant is awesome, VA is mindfucking my case :/
25 attempts 10 wrong :/ (CAT 2008)
Will try. Invite kare rakho. Kahaan pe hai woh bhi bata diyo. I can come to andheri :)
25 attempts 10 wrong :/ (CAT 2008)
Will try. Invite kare rakho. Kahaan pe hai woh bhi bata diyo. I can come to andheri :)
Wow! The solution was just damn brilliant.
Learnt something.
Nope. Koi bhi mock deneka mood nahi. Saala quant ne pooch pakadke rakhi hai. :(
Raat 10 baje confy hai, aayega na?
Learnt something.
Nope. Koi bhi mock deneka mood nahi. Saala quant ne pooch pakadke rakhi hai. :(
Raat 10 baje confy hai, aayega na?
1
We are wrong, the image soln is correct :/
Stupid bloody tricky sums :/
Stupid bloody tricky sums :/
1
Bhai tu kya machine hai?
Sacchi main designer hai....Scale leke lines khinchta hai kya?Itna precise? :P
Sacchi main designer hai....Scale leke lines khinchta hai kya?Itna precise? :P
1
it has to be D den....though d soln is B.....dint take pains to understand it bcoz it had to be D.....newyas here is d soln
![]()
1
max{|x|, |y|} = 3
When |x|>|y|
|x| = 3 or x= +-3
As long as |y|<3
ie. x = 3 or x= -3 for any value of y between +3 and -3
When |y|>|x|
|y| = 3 or y= +-3
As long as |x|<3
ie. y = 3 or y= -3 for any value of x between +3 and -3
When |x| = |y| = 3
(3,3) (-3,3) (3,-3), ...
When |x|>|y|
|x| = 3 or x= +-3
As long as |y|<3
ie. x = 3 or x= -3 for any value of y between +3 and -3
When |y|>|x|
|y| = 3 or y= +-3
As long as |x|<3
ie. y = 3 or y= -3 for any value of x between +3 and -3
When |x| = |y| = 3
(3,3) (-3,3) (3,-3), ...
3
Na na na :P
circle na
Kaise?
Square?
1
The distance of any point P(x,y) from the origin is defined as then all such possible point P will lie on the circumference of – Add to my aan equilateral triangle ba square circle da right triangle ea hexagon
1
then all
such possible point P will lie on the circumference of –
x+y = 12
xy <= 36
Q = 0.5log_2 (xy) - 3 = log_2 3 - 2
CPLC dega?
xy <= 36
Q = 0.5log_2 (xy) - 3 = log_2 3 - 2
CPLC dega?
log2 x-7=log2(5-y)
log 5-y (x-7)=1
x-7=5-y
x+y=12...GIVEN
log2 x^1/2- log2(8/rooty)
log2 root(xy)/8 should be maximum.
xy is max when x=y=6
log2(3/4)
log2 3-2 ANS
log 5-y (x-7)=1
x-7=5-y
x+y=12...GIVEN
log2 x^1/2- log2(8/rooty)
log2 root(xy)/8 should be maximum.
xy is max when x=y=6
log2(3/4)
log2 3-2 ANS
The original equation becomes,
log(x-7) = log(5-y)
x - 7 = 5 - y
x + y = 12.
The value of logx(base4) - log(8/rt[y])(base2) = logrt[x](base2) - log8(base2) + logrt[y](base2) = logrt[xy](base2) - 3.
For a constant sum, product will be max when x = y.
x = y = 6.
logrt[36](bas...
log(x-7) = log(5-y)
x - 7 = 5 - y
x + y = 12.
The value of logx(base4) - log(8/rt[y])(base2) = logrt[x](base2) - log8(base2) + logrt[y](base2) = logrt[xy](base2) - 3.
For a constant sum, product will be max when x = y.
x = y = 6.
logrt[36](bas...
1